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Saturday, 31 October

JEE Main · Physics · Work, Energy and Power

3D Vector Calculation of Power

JEE Main asked 3D Vector Calculation of Power 3 times in 3 of the 108 shifts Lumi analysed, in 2024, 2025 and 2026. It belongs to Power, in Work, Energy and Power (Physics). The longest wait between two years asking it was 1 year.

Updated 2026-10-24

Times asked
3
in 3 shifts
Years
3 of 8
First asked
2024
last in 2026
Pattern
New since 2024
across the analysed shifts

Questions on this idea a shift, by year

2017–2026. Asked in 2024, 2025 and 2026. Years differ in how many shifts Lumi analysed, so each year is scaled to one shift of 25 Physics questions.

00.10.20’170’200’210’220’230.05’240.13’250.11’26

Raw count: 2017: 0 in 1 shift · 2020: 0 in 12 shifts · 2021: 0 in 24 shifts · 2022: 0 in 24 shifts · 2023: 0 in 12 shifts · 2024: 1 in 18 shifts · 2025: 1 in 8 shifts · 2026: 1 in 9 shifts.

Shift by shift

Each square is one analysed shift, in date order. Open a filled one for that paper.

  • 20261 of 9
  • 20251 of 8
  • 20241 of 18
  • 20230 of 12
  • 20220 of 24
  • 20210 of 24
  • 20200 of 12
  • 20170 of 1

Asked in that shift More than once Not asked

How JEE Main framed it

Single correct is the usual form. Skill tested: multi-step.

  • Instantaneous power from time-dependent force
  • Power from time-dependent vector force

Difficulty

Easy 0Medium 3Hard 0

1 of the 3 questions had a numerical answer.

Every question

All 3 questions

From the official JEE Main shift papers, newest first. Open one for the full question, the options and the official answer.

  1. 4 Apr 2026, Shift 1 · Q49A body of mass 22 kg begins to move under the influence of time dependent force F⃗=(2t i^+6t2 j^)\vec{F}=\left(2t\,\hat{i}+6t^2\,\hat{j}\right) N, where…MediumNumerical value
  2. 7 Apr 2025, Shift 1 · Q28An object of mass 1000 g experiences a time dependent force F⃗=(2t i^+3t2 j^)N\vec{F} = \left(2t\,\hat{i} + 3t^2\,\hat{j}\right)\mathrm{N}. The power…MediumSingle correct
  3. 31 Jan 2024, Shift 2 · Q35A body of mass 2 kg begins to move under the action of a time dependent force given by F⃗=(6t i^+6t2 j^)\vec{F}=\left(6t\,\hat{i}+6t^2\,\hat{j}\right) N.…MediumSingle correct

Shifts: 31 Jan 2024, Shift 2, 7 Apr 2025, Shift 1, 4 Apr 2026, Shift 1.

Same topic

Other ideas in Power

Power has 6 ideas JEE Main has asked; 4 of them came up in more than one question.

Topic analysisChapter analysisStudy this chapterAll repeated ideas