Learn

Saturday, 31 October

JEE Main · Maths · Application of Derivatives

Equation of Tangent

JEE Main asked Equation of Tangent 3 times in 3 of the 108 shifts Lumi analysed, in 2021 and 2023. It belongs to Tangents and Normals, in Application of Derivatives (Maths). The longest wait between two years asking it was 2 years. In 2021 it came in more than one shift of the same year.

Updated 2026-10-24

Times asked
3
in 3 shifts
Years
2 of 8
First asked
2021
last in 2023
Pattern
Occasional
across the analysed shifts

Questions on this idea a shift, by year

2017–2026. Asked in 2021 and 2023. Years differ in how many shifts Lumi analysed, so each year is scaled to one shift of 25 Maths questions.

00.050.10’170’200.07’210’220.07’230’240’250’26

Raw count: 2017: 0 in 1 shift · 2020: 0 in 12 shifts · 2021: 2 in 24 shifts · 2022: 0 in 24 shifts · 2023: 1 in 12 shifts · 2024: 0 in 18 shifts · 2025: 0 in 8 shifts · 2026: 0 in 9 shifts.

Shift by shift

Each square is one analysed shift, in date order. Open a filled one for that paper.

  • 20260 of 9
  • 20250 of 8
  • 20240 of 18
  • 20231 of 12
  • 20220 of 24
  • 20212 of 24
  • 20200 of 12
  • 20170 of 1

Asked in that shift More than once Not asked

How JEE Main framed it

Single correct is the usual form. Skill tested: multi-step.

  • Tangent, parallel line and distance between points
  • Tangent to curve defined by integral

Difficulty

Easy 1Medium 2Hard 0

1 of the 3 questions had a numerical answer.

Every question

All 3 questions

From the official JEE Main shift papers, newest first. Open one for the full question, the options and the official answer.

  1. 6 Apr 2023, Shift 1 · Q28Let the tangent to the curve x2+2x−4y+9=0x^2+2x-4y+9=0 at the point P(1,3)P(1,3) on it meet the yy-axis at A. Let the line passing through P and…MediumNumerical value
  2. 24 Feb 2021, Shift 2 · Q70If the curve y=ax2+bx+cy=ax^2+bx+c, x∈x\in R, passes through the point (1, 2) and the tangent line to this curve at origin is y=xy=x, then the…EasySingle correct
  3. 4 Aug 2021, Shift 1 · Q70The equation of the tangent to the curve y=∫x2x3dt1+t2y=\int_{x^2}^{x^3}\frac{dt}{\sqrt{1+t^2}} at the point whose abscissa is 1, isMediumSingle correct

Shifts: 24 Feb 2021, Shift 2, 4 Aug 2021, Shift 1, 6 Apr 2023, Shift 1.

Same topic

Other ideas in Tangents and Normals

Tangents and Normals has 20 ideas JEE Main has asked; 7 of them came up in more than one question. The 12 most asked are below.

Topic analysisChapter analysisStudy this chapterAll repeated ideas