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Saturday, 31 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 3 April 2025, Shift 1, Maths Q17

Question 17 of 75 in this shift, Maths question 17 of 25, Section A.

Let f(x)={(1+ax)1/x,x<01+b,x=0(x+4)1/2−2(x+c)1/3−2,x>0f(x) = \begin{cases} (1+ax)^{1/x}, & x < 0 \\ 1+b, & x = 0 \\ \dfrac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2}, & x > 0 \end{cases} be continuous at x=0x = 0. Then eabce^a bc is equal to:
  1. (1)48Official answer
  2. (2)64
  3. (3)72
  4. (4)36

Official answer

Option 1

NTA final key.