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Saturday, 31 October

JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 8 April 2026, Shift 2, Maths Q19

Question 19 of 75 in this shift, Maths question 19 of 25, Section A.

Let f(x)={13,x≤π/2b(1−sin⁡x)(π−2x)2,x>π/2f(x) = \begin{cases} \frac{1}{3}, & x \le \pi/2 \\ \frac{b(1 - \sin x)}{(\pi - 2x)^2}, & x > \pi/2 \end{cases}. If ff is continuous at x=π/2x = \pi/2, then the value of ∫03b−6∣x2+2x−3∣ dx\int_0^{3b-6} |x^2 + 2x - 3|\,dx is :
  1. (1)5
  2. (2)2
  3. (3)3
  4. (4)4Official answer

Official answer

Option 4

NTA final key.

Chapter
Continuity and Differentiability
Topic
Continuity and Differentiability
Idea tested
Finding Unknowns using Continuity

Same idea in other shifts

Asked 3× in all
  1. 3 Apr 2025, Shift 1 · Q17Let f(x)={(1+ax)1/x,x<01+b,x=0(x+4)1/2−2(x+c)1/3−2,x>0f(x) = \begin{cases} (1+ax)^{1/x}, & x < 0 \\ 1+b, & x = 0 \\ \dfrac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2}, & x > 0 \end{cases} be…MediumSingle correct
  2. 3 Aug 2021, Shift 1 · Q66Suppose that the function…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.