Learn

Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 4 April 2024, Shift 2, Physics Q56

Question 56 of 90 in this shift, Physics question 26 of 30, Section B.

The displacement of a particle executing SHM is given by x=10sin⁡(wt+π3)mx = 10\sin\left(wt + \frac{\pi}{3}\right)m. The time period of motion is 3.14 s. The velocity of the particle at t=0t = 0 is __________ m/sm/s.

Official answer

10

NTA final key.