JEE Main 2020 · PhysicsMultiple choiceOtherMediumData or graph
JEE Main 2 September 2020, Shift 2, Physics Q2
Question 2 of 75 in this shift, Physics question 2 of 25.
The displacement time graph of a particle executing S.H.M. is given in figure : (sketch is schematic and not to scale)
Which of the following statements is/are true for this motion ?
(A) The force is zero at
(B) The acceleration is maximum at
(C) The speed is maximum at
(D) The P.E. is equal to K.E. of the oscillation at
The figure, in words
Displacement (vertical axis) versus time (s) (horizontal axis) graph. Curve starts above the axis at t = 0 (point O marked on the axis), falls to cross the time axis at T/4, dips below the axis to a trough above which the label 2T/4 is printed (dot on the axis at 2T/4), returns to the axis at 3T/4, then rises into a hump above the axis that ends on the axis at 5T/4. Labels printed under the axis: T/4, 3T/4, T (dot on axis), 5T/4.- (1)(A), (B) and (D)
- (2)(A) and (D)
- (3)(A), (B) and (C)Official answer
- (4)(B), (C) and (D)
Official answer
Option 3
NTA final key (Sep 2020).
- Chapter
- Oscillations
- Topic
- SHM Equations
- Idea tested
- Velocity and Accel vs Time