JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 27 June 2022, Shift 2, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

The equation of a particle executing simple harmonic motion is given by

x = \sin \pi\left(t + \frac{1}{3}\right)

m. At

t

= 1s, the speed of particle will be (Given:

\pi

= 3.14) -

(1)0 cm s $^{-1}$
(2)157 cm s $^{-1}$ Official answer
(3)272 cm s $^{-1}$
(4)314 cm s $^{-1}$

Official answer

Option 2

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: Velocity and Accel vs Time

Same idea in other shifts

Asked 4× in all

2 Apr 2026, Shift 2 · Q45The equation of motion of a particle is given by $x = a\sin\left(50t + \frac{\pi}{3}\right)$ cm. The particle will come to rest at time…MediumSingle correct
4 Apr 2024, Shift 2 · Q56The displacement of a particle executing SHM is given by $x = 10\sin\left(wt + \frac{\pi}{3}\right)m$ . The time period of motion is 3.14…EasyNumerical value
2 Sep 2020, Shift 2 · Q2The displacement time graph of a particle executing S.H.M. is given in figure : (sketch is schematic and not to scale) Which of the…MediumOtherHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.