JEE Main 2023 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 6 April 2023, Shift 1, Physics Q39

Question 39 of 90 in this shift, Physics question 9 of 30, Section A.

A particle is moving with constant speed in a circular path. When the particle turns by an angle

90^\circ

, the ratio of instantaneous velocity to its average velocity is

\pi : x\sqrt2

. The value of

x

will be -

(1)7
(2)5
(3)2Official answer
(4)1

Official answer

Option 3

NTA final key.

Chapter: Motion in a Plane
Topic: Kinematics in 2D
Idea tested: Uniform Circular Motion

Same idea in other shifts

Asked 3× in all

6 Apr 2023, Shift 2 · Q32As shown in the figure, a particle is moving with constant speed $\pi$ m/s. Considering its motion from A to B, the magnitude of the…MediumDiagram basedHas a figure
25 Jun 2022, Shift 2 · Q37For a particle in uniform circular motion, the acceleration $\vec{a}$ at any point $P(R,\theta)$ on the circular path of radius $R$ is…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.