JEE Main 2022 (25 Jun, Shift 2) Physics Q37: For a…

Question

For a particle in uniform circular motion, the acceleration $\vec{a}$ at any point $P(R,	heta)$ on the circular path of radius $R$ is (when $	heta$ is measured from the positive $x$-axis and $v$ is uniform speed) :

Accepted Answer

Option 3: $-\frac{v^2}{R}\cos	heta\,\hat{i} - \frac{v^2}{R}\sin	heta\,\hat{j}$

Answer

$-\frac{v^2}{R}\sin	heta\,\hat{i} + \frac{v^2}{R}\cos	heta\,\hat{j}$

Answer

$-\frac{v^2}{R}\cos	heta\,\hat{i} + \frac{v^2}{R}\sin	heta\,\hat{j}$

Answer

$-\frac{v^2}{R}\cos	heta\,\hat{i} - \frac{v^2}{R}\sin	heta\,\hat{j}$

Answer

$-\frac{v^2}{R}\hat{i} + \frac{v^2}{R}\hat{j}$

JEE Main 25 June 2022, Shift 2, Physics Q37

Same idea in other shifts