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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 26 June 2022, Shift 2, Maths Q8

Question 8 of 90 in this shift, Maths question 8 of 30, Section A.

If ∫1x1−x1+x dx=g(x)+c\int \frac{1}{x}\sqrt{\frac{1 - x}{1 + x}}\, dx = g(x) + c, g(1)=0g(1) = 0, then g(12)g\left(\frac{1}{2}\right) is equal to :
  1. (1)log⁡e(3−13+1)+π3\log_e\left(\frac{\sqrt{3} - 1}{\sqrt{3} + 1}\right) + \frac{\pi}{3}Official answer
  2. (2)log⁡e(3+13−1)+π3\log_e\left(\frac{\sqrt{3} + 1}{\sqrt{3} - 1}\right) + \frac{\pi}{3}
  3. (3)log⁡e(3+13−1)−π3\log_e\left(\frac{\sqrt{3} + 1}{\sqrt{3} - 1}\right) - \frac{\pi}{3}
  4. (4)12log⁡e(3−13+1)−π6\frac{1}{2}\log_e\left(\frac{\sqrt{3} - 1}{\sqrt{3} + 1}\right) - \frac{\pi}{6}

Official answer

Option 1

NTA final key.

Chapter
Integrals