JEE Main 2022 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 26 June 2022, Shift 2, Maths Q7

Question 7 of 90 in this shift, Maths question 7 of 30, Section A.

The area of the region bounded by

y^2 = 8x

and

y^2 = 16(3 - x)

is equal to:

(1) $\frac{32}{3}$
(2) $\frac{40}{3}$
(3) $16$ Official answer
(4) $19$

Official answer

Option 3

NTA final key.

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Area Between Two Standard Parabolas

Same idea in other shifts

Asked 6× in all

4 Apr 2026, Shift 2 · Q18The area of the region bounded by the curves $x+3y^2=0$ and $x+4y^2=1$ is equal to:EasySingle correct
5 Apr 2024, Shift 1 · Q27The area of the region enclosed by the parabolas $y=x^2-5x$ and $y=7x-x^2$ is ________.EasyNumerical value
1 Feb 2024, Shift 2 · Q26The sum of squares of all possible values of $k$ , for which area of the region bounded by the parabolas $2y^2=kx$ and $ky^2=2(y-x)$ is…HardNumerical value
25 Jun 2022, Shift 2 · Q6The area of the region enclosed between the parabolas $y^2 = 2x - 1$ and $y^2 = 4x - 3$ isMediumSingle correct
24 Feb 2021, Shift 2 · Q80The area of the region : R = {(x, y) : $5x^2\leq y\leq2x^2+9$ } is :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.