JEE Main 2026 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 4 April 2026, Shift 2, Maths Q18

Question 18 of 75 in this shift, Maths question 18 of 25, Section A.

The area of the region bounded by the curves

x+3y^2=0

and

x+4y^2=1

is equal to:

(1) $\frac13$
(2) $\frac23$
(3) $\frac43$ Official answer
(4) $\frac53$

Official answer

Option 3

NTA final key.

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Area Between Two Standard Parabolas

Same idea in other shifts

Asked 6× in all

5 Apr 2024, Shift 1 · Q27The area of the region enclosed by the parabolas $y=x^2-5x$ and $y=7x-x^2$ is ________.EasyNumerical value
1 Feb 2024, Shift 2 · Q26The sum of squares of all possible values of $k$ , for which area of the region bounded by the parabolas $2y^2=kx$ and $ky^2=2(y-x)$ is…HardNumerical value
25 Jun 2022, Shift 2 · Q6The area of the region enclosed between the parabolas $y^2 = 2x - 1$ and $y^2 = 4x - 3$ isMediumSingle correct
26 Jun 2022, Shift 2 · Q7The area of the region bounded by $y^2 = 8x$ and $y^2 = 16(3 - x)$ is equal to:MediumSingle correct
24 Feb 2021, Shift 2 · Q80The area of the region : R = {(x, y) : $5x^2\leq y\leq2x^2+9$ } is :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.