JEE Main 2025 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 4 April 2025, Shift 2, Maths Q25

Question 25 of 75 in this shift, Maths question 25 of 25, Section B.

\int\frac{\left(\sqrt{1+x^2}+x\right)^{10}}{\left(\sqrt{1+x^2}-x\right)^{9}}dx=\frac{1}{m}\left(\left(\sqrt{1+x^2}+x\right)^{n}\left(n\sqrt{1+x^2}-x\right)\right)+C

where C is the constant of integration and

m,n\in\mathbf{N}

, then

m+n

is equal to __________.

Official answer

379

NTA final key.

Chapter: Integrals
Topic: Integration by Substitution
Idea tested: Hyperbolic Substitution

Same topic in other shifts

All Integration by Substitution questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.