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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 25 February 2021, Shift 1, Physics Q26

Question 26 of 90 in this shift, Physics question 26 of 30, Section B.

The electric field in a region is given by E⃗=(35E0i^+45E0j^)NC\vec{E}=\left(\frac{3}{5}E_0\hat{i}+\frac{4}{5}E_0\hat{j}\right)\frac{N}{C}. The ratio of flux of reported field through the rectangular surface of area 0.2 m2^2 (parallel to y−zy-z plane) to that of the surface of area 0.3 m2^2 (parallel to x−zx-z plane) is a : b, where a = __________ . [Here i^\hat{i}, j^\hat{j} and k^\hat{k} are unit vectors along xx, yy and zz-axes respectively]

Official answer

1

NTA final key.