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Saturday, 31 October

JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 9 January 2020, Shift 2, Physics Q22

Question 22 of 75 in this shift, Physics question 22 of 25, Section B.

An electric field E⃗=4x i^−(y2+1) j^\vec{E} = 4x\,\hat{i} - (y^2+1)\,\hat{j} N/C passes through the box shown in figure. The flux of the electric field through surfaces ABCD and BCGF are marked as ϕI\phi_I and ϕII\phi_{II} respectively. The difference between (ϕI−ϕII)(\phi_I - \phi_{II}) is (in Nm2^2/C) ______.

The figure, in words

Rectangular box in x-y-z axes with vertices A(0,0,2), B(3,0,2), C(3,2,2), D(0,2,2), E(0,0,0), F(3,0,0), G(3,2,0), H(0,2,0).

Official answer

-48.00

NTA final key (Jan 2020).