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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 25 February 2021, Shift 1, Physics Q25

Question 25 of 90 in this shift, Physics question 25 of 30, Section B.

The potential energy (U) of a diatomic molecule is a function dependent on r (interatomic distance) as U=αr10−βr5−3U=\frac{\alpha}{r^{10}}-\frac{\beta}{r^{5}}-3 where, α\alpha and β\beta are positive constants. The equilibrium distance between two atoms will be (2αβ)ab\left(\frac{2\alpha}{\beta}\right)^{\frac{a}{b}}, where a = __________ .

Official answer

1

NTA final key.

Chapter
Work, Energy and Power
Topic
Work and Kinetic Energy
Idea tested
Potential Energy Curves and Equilibrium

Same idea in other shifts

Asked 2× in all
  1. 24 Jun 2022, Shift 2 · Q41Potential energy as a function of rr is given by U=Ar10−Br5U=\frac{A}{r^{10}}-\frac{B}{r^{5}}, where rr is the interatomic distance, A and B are…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.