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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceMatch the listMediumRecall

JEE Main 24 February 2021, Shift 2, Chemistry Q50

Question 50 of 90 in this shift, Chemistry question 20 of 30, Section A.

Match List - I and List - II. List - I | List - II (a) R−C(=O)−Cl→R−CHO\mathrm{R-C(=O)-Cl \rightarrow R-CHO} | (i) Br2\mathrm{Br_2}/NaOH (b) R−CH2−COOH→R−CH(Cl)−COOH\mathrm{R-CH_2-COOH \rightarrow R-CH(Cl)-COOH} | (ii) H2\mathrm{H_2}/Pd−BaSO4-\mathrm{BaSO_4} (c) R−C(=O)−NH2→R−NH2\mathrm{R-C(=O)-NH_2 \rightarrow R-NH_2} | (iii) Zn(Hg)/Conc. HCl (d) R−C(=O)−CH3→R−CH2−CH3\mathrm{R-C(=O)-CH_3 \rightarrow R-CH_2-CH_3} | (iv) Cl2\mathrm{Cl_2}/Red P, H2O\mathrm{H_2O} Choose the correct answer from the options given below :

The figure, in words

In List-I each C=O is drawn with the O above the carbon; in (b) the Cl is drawn below the CH carbon.
  1. (1)(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
  2. (2)(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
  3. (3)(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
  4. (4)(a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)Official answer

Official answer

Option 4

NTA final key.