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JEE Main 24 February 2021, Shift 2, Chemistry Q51

Question 51 of 90 in this shift, Chemistry question 21 of 30, Section B.

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of

\mathrm{O_2}

for complete oxidation and produces 4 times its own volume of

\mathrm{CO_2}

is

\mathrm{C_xH_y}

. The value of

y

is __________.

Official answer

8

NTA final key.

Chapter: Some Basic Concepts of Chemistry
Topic: Stoichiometry
Idea tested: Eudiometry and Gas Mixture Analysis

Same idea in other shifts

Asked 2× in all

1 Feb 2024, Shift 2 · Q8110 mL of gaseous hydrocarbon on combustion gives 40 mL of $\mathrm{CO_2(g)}$ and 50 mL of water vapour. Total number of carbon and…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.