JEE Main 2020 · ChemistryMultiple choiceMatch the listEasyRecall

JEE Main 6 September 2020, Shift 2, Chemistry Q29

Question 29 of 75 in this shift, Chemistry question 4 of 25.

The correct match between Item - I (starting material) and Item - II (reagent) for the preparation of benzaldehyde is : Item - I / Item - II (I) Benzene (P) HCl and

\mathrm{SnCl_2}

\mathrm{H_3O^+}

(II) Benzonitrile (Q)

\mathrm{H_2}

, Pd-

\mathrm{BaSO_4}

, S and quinoline (III) Benzoyl Chloride (R) CO, HCl and

\mathrm{AlCl_3}

(1)(I) - (R), (II) - (P) and (III) - (Q)Official answer
(2)(I) - (R), (II) - (Q) and (III) - (P)
(3)(I) - (Q), (II) - (R) and (III) - (P)
(4)(I) - (P), (II) - (Q) and (III) - (R)

Official answer

Option 1

NTA final key (Sep 2020).

Chapter: Aldehydes, Ketones and Carboxylic Acids
Topic: Carboxylic Acids and Derivatives
Idea tested: Rosenmund Reduction

Same idea in other shifts

Asked 6× in all

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.