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JEE Main 31 August 2021, Shift 2, Chemistry Q51

Question 51 of 90 in this shift, Chemistry question 21 of 30, Section B.

Sodium oxide reacts with water to produce sodium hydroxide. 20.0 g of sodium oxide is dissolved in 500 mL of water. Neglecting the change in volume, the concentration of the resulting NaOH solution is __________

\times 10^{-1}

M. (Nearest integer) [Atomic mass : Na = 23.0, O = 16.0, H = 1.0 ]

Official answer

NTA final key.

Chapter: Some Basic Concepts of Chemistry
Topic: Mole Concept
Idea tested: Molarity Calculation

Same idea in other shifts

Asked 16× in all

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26 Jul 2022, Shift 1 · Q85When 800 mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g of nitric acid is evaporated. The…MediumNumerical value
26 Jun 2022, Shift 1 · Q61A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is :…EasySingle correct
4 Aug 2021, Shift 1 · Q51A solution of $\mathrm{H_2SO_4}$ has 30% $\mathrm{H_2SO_4}$ by mass and a density of 1.25 g mL $^{-1}$ . The molarity of the solution is…EasyNumerical value
26 Aug 2021, Shift 2 · Q51100 mL of $\mathrm{Na_3PO_4}$ solution contains 3.45 g of sodium. The molarity of the solution is __________ $\times 10^{-2}$ mol…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.