JEE Main 2022 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 26 July 2022, Shift 1, Chemistry Q85

Question 85 of 90 in this shift, Chemistry question 25 of 30, Section B.

When 800 mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is

x \times 10^{-2}

M. (Nearest Integer) (Molar mass of nitric acid is 63 g mol

^{-1}

)

Official answer

NTA final key.

Chapter: Some Basic Concepts of Chemistry
Topic: Mole Concept
Idea tested: Molarity Calculation

Same idea in other shifts

Asked 16× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.