JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation
JEE Main 26 August 2021, Shift 2, Chemistry Q51
Question 51 of 90 in this shift, Chemistry question 21 of 30, Section B.
100 mL of solution contains 3.45 g of sodium. The molarity of the solution is __________ mol . (Nearest integer)
[Atomic Masses - Na : 23.0 u, O : 16.0 u, P : 31.0 u]
Official answer
50
NTA final key.
- Topic
- Mole Concept
- Idea tested
- Molarity Calculation