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Saturday, 31 October

JEE Main · Chemistry · Solutions

Thermodynamic Calculation of Cryoscopic Constant

JEE Main asked Thermodynamic Calculation of Cryoscopic Constant once in the 108 shifts Lumi analysed, on 4 Apr 2025, Shift 2. It belongs to Colligative Properties, in Solutions (Chemistry).

Updated 2026-10-24

Times asked
1
in 1 shift
Years
1 of 8
First asked
2025
the only year
Pattern
New since 2024
asked once so far

Questions on this idea a shift, by year

2017–2026. Asked in 2025. Years differ in how many shifts Lumi analysed, so each year is scaled to one shift of 25 Chemistry questions.

00.10.20’170’200’210’220’230’240.13’250’26

Raw count: 2017: 0 in 1 shift · 2020: 0 in 12 shifts · 2021: 0 in 24 shifts · 2022: 0 in 24 shifts · 2023: 0 in 12 shifts · 2024: 0 in 18 shifts · 2025: 1 in 8 shifts · 2026: 0 in 9 shifts.

Shift by shift

Each square is one analysed shift, in date order. Open a filled one for that paper.

  • 20260 of 9
  • 20251 of 8
  • 20240 of 18
  • 20230 of 12
  • 20220 of 24
  • 20210 of 24
  • 20200 of 12
  • 20170 of 1

Asked in that shift More than once Not asked

How JEE Main framed it

Two statements is the usual form. Skill tested: conceptual.

  • Statement i/ii on cryoscopic constant

Difficulty

Easy 0Medium 1Hard 0

The question was multiple choice.

Every question

The question

From the official JEE Main shift papers, newest first. Open one for the full question, the options and the official answer.

  1. 4 Apr 2025, Shift 2 · Q53Given below are two statements : Statement (I) : Molal depression constant KfK_f is given by M1RTfΔSfus\frac{M_1RT_f}{\Delta S_{fus}}, where…MediumTwo statements

Shift: 4 Apr 2025, Shift 2.

Same topic

Other ideas in Colligative Properties

Colligative Properties has 21 ideas JEE Main has asked; 13 of them came up in more than one question. The 12 most asked are below.

Topic analysisChapter analysisStudy this chapterAll repeated ideas