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Saturday, 31 October

JEE Main 2025 · PhysicsNumerical answerNumerical valueHardMulti-step

JEE Main 7 April 2025, Shift 1, Physics Q49

Question 49 of 75 in this shift, Physics question 24 of 25, Section B.

For ac circuit shown in figure, R = 100 kΩ\Omega and C = 100 pF and the phase difference between Vin\mathrm{V_{in}} and (VB−VA)(\mathrm{V_B} - \mathrm{V_A}) is 90∘90^\circ. The input signal frequency is 10x10^x rad/sec, where 'x' is ______.

The figure, in words

Bridge circuit driven by source V_in: left arm is R in series with C (to the bottom wire), right arm is C in series with R; V_A is taken at the junction of R and C in the left arm and V_B at the junction of C and R in the right arm.

Official answer

5

NTA final key.

Chapter
Alternating Current
Topic
Phasor Diagrams
Idea tested
Phase Shifting Networks

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.