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Saturday, 31 October

JEE Main 2025 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 4 April 2025, Shift 2, Physics Q48

Question 48 of 75 in this shift, Physics question 23 of 25, Section B.

An inductor of self inductance 1 H is connected in series with a resistor of 100 π100\,\pi ohm and an ac supply of 100 π100\,\pi volt, 50 Hz. Maximum current flowing in the circuit is ________ A.

Official answer

1

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 8 Apr 2024, Shift 2 · Q43A coil of negligible resistance is connected in series with 90 Ω90\ \Omega resistor across 120120 V, 6060 Hz supply. A voltmeter reads 3636 V…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.