/

Learn

Saturday, 31 October

/

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 31 January 2024, Shift 2, Physics Q51

Question 51 of 90 in this shift, Physics question 21 of 30, Section B.

A body of mass '

m

' is projected with a speed '

u

' making an angle of

45^\circ

with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as

\frac{\sqrt{2}mu^3}{Xg}

. The value of '

X

' is ________.

Official answer

8

NTA final key.

Chapter: Motion in a Plane
Topic: Angular Momentum
Idea tested: Angular Momentum of Projectile at Maximum Height

Same idea in other shifts

Asked 2× in all

30 Jan 2024, Shift 1 · Q32A particle of mass m is projected with a velocity 'u' making an angle of $30^\circ$ with the horizontal. The magnitude of angular momentum…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.