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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 31 January 2024, Shift 2, Maths Q17

Question 17 of 90 in this shift, Maths question 17 of 30, Section A.

The shortest distance, between lines L1L_1 and L2L_2, where L1:x−12=y+1−3=z+42L_1:\frac{x-1}{2}=\frac{y+1}{-3}=\frac{z+4}{2} and L2L_2 is the line, passing through the points A(−4,4,3)A(-4,4,3), B(−1,6,3)B(-1,6,3) and perpendicular to the line x−3−2=y3=z−11\frac{x-3}{-2}=\frac{y}{3}=\frac{z-1}{1}, is
  1. (1)24117\frac{24}{\sqrt{117}}
  2. (2)42117\frac{42}{\sqrt{117}}
  3. (3)121221\frac{121}{\sqrt{221}}
  4. (4)141221\frac{141}{\sqrt{221}}Official answer

Official answer

Option 4

NTA final key.

Same idea in other shifts

Asked 15× in all
  1. 6 Apr 2026, Shift 2 · Q14The shortest distance between the lines x−41=y−32=z−2−3\frac{x-4}{1}=\frac{y-3}{2}=\frac{z-2}{-3} and x+22=y−64=z−5−5\frac{x+2}{2}=\frac{y-6}{4}=\frac{z-5}{-5} is :EasySingle correct
  2. 7 Apr 2025, Shift 1 · Q14If the shortest distance between the lines x−12=y−23=z−34\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4} and…MediumSingle correct
  3. 8 Apr 2024, Shift 2 · Q16If the shortest distance between the lines x−λ2=y−43=z−34\frac{x-\lambda}{2} = \frac{y-4}{3} = \frac{z-3}{4} and…MediumSingle correct
  4. 9 Apr 2024, Shift 1 · Q16The shortest distance between the lines x−34=y+7−11=z−15\frac{x-3}{4}=\frac{y+7}{-11}=\frac{z-1}{5} and x−53=y−9−6=z+21\frac{x-5}{3}=\frac{y-9}{-6}=\frac{z+2}{1} is :EasySingle correct
  5. 1 Feb 2024, Shift 1 · Q16If the shortest distance between the lines x−λ−2=y−21=z−11\frac{x-\lambda}{-2}=\frac{y-2}{1}=\frac{z-1}{1} and…MediumSingle correct
  6. 27 Jan 2024, Shift 1 · Q18If the shortest distance between the lines x−41=y+12=z−3\dfrac{x-4}{1}=\dfrac{y+1}{2}=\dfrac{z}{-3} and…MediumSingle correct
  7. 30 Jan 2024, Shift 1 · Q28If d1d_1 is the shortest distance between the lines x+1=2y=−12zx+1=2y=-12z, x=y+2=6z−6x=y+2=6z-6 and d2d_2 is the shortest distance between the lines…MediumNumerical value
  8. 10 Apr 2023, Shift 1 · Q15The shortest distance between the lines x+21=y−2=z−52\frac{x+2}{1}=\frac{y}{-2}=\frac{z-5}{2} and x−41=y−12=z+30\frac{x-4}{1}=\frac{y-1}{2}=\frac{z+3}{0} isEasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.