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Saturday, 31 October

JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyApplication

JEE Main 31 January 2024, Shift 1, Chemistry Q88

Question 88 of 90 in this shift, Chemistry question 28 of 30, Section B.

CH3CH2Br+NaOH\mathrm{CH_3CH_2Br + NaOH} with C2H5OH\mathrm{C_2H_5OH} gives Product A, and with H2O\mathrm{H_2O} gives Product B. The total number of hydrogen atoms in product A and product B is _________.

The figure, in words

Reaction scheme: CH3CH2Br + NaOH branches to Product A (solvent C2H5OH, top arrow) and Product B (solvent H2O, bottom arrow)

Official answer

10

NTA final key.

Same idea in other shifts

Asked 3× in all
  1. 4 Apr 2024, Shift 2 · Q77→ΔKOH(alc)\xrightarrow[\Delta]{\mathrm{KOH(alc)}} major product "P" Product P isMediumDiagram basedHas a figure
  2. 3 Sep 2020, Shift 2 · Q45The major product in the following reaction is : [figure] →Heatt-BuOH\xrightarrow[\text{Heat}]{\text{t-BuOH}}MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.