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Saturday, 31 October

JEE Main 2024 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 31 January 2024, Shift 1, Maths Q28

Question 28 of 90 in this shift, Maths question 28 of 30, Section B.

Let the foci and length of the latus rectum of an ellipse x2a2+y2b2=1, a>b\frac{x^2}{a^2}+\frac{y^2}{b^2}=1,\ a>b be (±5,0)(\pm5,0) and 50\sqrt{50}, respectively. Then, the square of the eccentricity of the hyperbola x2b2−y2a2b2=1\frac{x^2}{b^2}-\frac{y^2}{a^2b^2}=1 equals ______

Official answer

51

NTA final key.

Same idea in other shifts

Asked 12× in all
  1. 4 Apr 2026, Shift 1 · Q22Consider the parabola P:y2=4kxP: y^2=4kx and the ellipse E:x2a2+y2b2=1E: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1. Let the line segment joining the points of…MediumNumerical value
  2. 7 Apr 2025, Shift 2 · Q12Let the length of a latus rectum of an ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 be 10. If its eccentricity is the minimum value of the…MediumSingle correct
  3. 5 Apr 2024, Shift 1 · Q15Let the line 2x+3y−k=02x+3y-k=0, k>0k>0, intersect the xx-axis and yy-axis at the points A and B, respectively. If the equation of the circle…MediumSingle correct
  4. 9 Apr 2024, Shift 1 · Q12Let f(x)=x2+9f(x)=x^2+9, g(x)=xx−9g(x)=\frac{x}{x-9} and a=f∘g(10)a=f\circ g(10), b=g∘f(3)b=g\circ f(3). If ee and ll denote the eccentricity and the length of the…EasySingle correct
  5. 1 Feb 2024, Shift 1 · Q13Let x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a>ba>b be an ellipse, whose eccentricity is 12\frac{1}{\sqrt{2}} and the length of the latusrectum…MediumSingle correct
  6. 31 Jan 2024, Shift 2 · Q14Let PP be a parabola with vertex (2,3)(2,3) and directrix 2x+y=62x+y=6. Let an ellipse E:x2a2+y2b2=1, a>bE:\frac{x^2}{a^2}+\frac{y^2}{b^2}=1,\ a>b, of…HardSingle correct
  7. 6 Apr 2023, Shift 2 · Q27Let the eccentricity of an ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 is reciprocal to that of the hyperbola 2x2−2y2=12x^2-2y^2=1. If the…HardNumerical value
  8. 27 Jul 2022, Shift 1 · Q24An ellipse E:x2a2+y2b2=1E : \dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1 passes through the vertices of the hyperbola…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.