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Saturday, 31 October

JEE Main 2024 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 31 January 2024, Shift 1, Maths Q22

Question 22 of 90 in this shift, Maths question 22 of 30, Section B.

If α\alpha denotes the number of solutions of ∣1−i∣x=2x|1-i|^x=2^x and β=(∣z∣arg⁡(z))\beta=\left(\frac{|z|}{\arg(z)}\right), where z=π4(1+i)4[1−πiπ+i+π−i1+πi]z=\frac{\pi}{4}(1+i)^4\left[\frac{1-\sqrt{\pi}i}{\sqrt{\pi}+i}+\frac{\sqrt{\pi}-i}{1+\sqrt{\pi}i}\right], i=−1i=\sqrt{-1}, then the distance of the point (α,β)(\alpha,\beta) from the line 4x−3y=74x-3y=7 is ______

Official answer

3

NTA final key.

Same idea in other shifts

Asked 13× in all
  1. 5 Apr 2024, Shift 1 · Q2Consider the following two statements : Statement I : For any two non-zero complex numbers z1,z2z_1, z_2,…HardTwo statements
  2. 6 Apr 2024, Shift 2 · Q3If z1,z2z_1, z_2 are two distinct complex number such that ∣z1−2z212−z1z2ˉ∣=2\left|\frac{z_1-2z_2}{\frac{1}{2}-z_1\bar{z_2}}\right|=2, thenHardSingle correct
  3. 1 Feb 2024, Shift 1 · Q1Let S={z∈C:∣z−1∣=1S=\{z\in\mathbb{C}:|z-1|=1 and (2−1)(z+zˉ)−i(z−zˉ)=22}(\sqrt{2}-1)(z+\bar{z})-i(z-\bar{z})=2\sqrt{2}\}. Let z1,z2∈Sz_1, z_2\in S be such that…HardSingle correct
  4. 29 Jan 2024, Shift 1 · Q3If z=12−2iz=\frac{1}{2}-2i is such that ∣z+1∣=αz+β(1+i)|z+1|=\alpha z+\beta(1+i), i=−1i=\sqrt{-1} and α,β∈R\alpha,\beta\in\mathbb{R}, then α+β\alpha+\beta is…EasySingle correct
  5. 30 Jan 2024, Shift 1 · Q2If z=x+iy, xy≠0z=x+iy,\ xy\neq0, satisfies the equation z2+izˉ=0z^2+i\bar{z}=0, then ∣z2∣|z^2| is equal to :MediumSingle correct
  6. 8 Apr 2023, Shift 1 · Q2If for z=α+iβz=\alpha+i\beta, ∣z+2∣=z+4(1+i)|z+2|=z+4(1+i), then α+β\alpha+\beta and αβ\alpha\beta are the roots of the equationMediumSingle correct
  7. 28 Jul 2022, Shift 2 · Q88Let z=a+ib, b≠0z=a+ib,\ b\neq 0 be complex numbers satisfying z2=zˉ⋅21−∣z∣z^2=\bar{z}\cdot 2^{1-|z|}. Then the least value of n∈Nn\in\mathbb{N}, such that…HardNumerical value
  8. 30 Jul 2022, Shift 2 · Q62Let z1=1+2iz_1 = 1 + 2i, z2=2+iz_2 = 2 + i, 1z1+1z2=6w\frac{1}{z_1}+\frac{1}{z_2}=\frac{6}{w}, and z=iw2−w‾z = \frac{iw}{2-\overline{w}}. Consider the statements…MediumTwo statements

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.