JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyConceptual

JEE Main 30 January 2024, Shift 2, Chemistry Q65

Question 65 of 90 in this shift, Chemistry question 5 of 30, Section A.

Reduction potential of ions are given below:

\mathrm{ClO_4^-}

E^\circ = 1.19\ V

;

\mathrm{IO_4^-}

E^\circ = 1.65\ V

;

\mathrm{BrO_4^-}

E^\circ = 1.74\ V

The correct order of their oxidising power is :

(1) $\mathrm{ClO_4^-} > \mathrm{IO_4^-} > \mathrm{BrO_4^-}$
(2) $\mathrm{IO_4^-} > \mathrm{BrO_4^-} > \mathrm{ClO_4^-}$
(3) $\mathrm{BrO_4^-} > \mathrm{IO_4^-} > \mathrm{ClO_4^-}$ Official answer
(4) $\mathrm{BrO_4^-} > \mathrm{ClO_4^-} > \mathrm{IO_4^-}$

Official answer

Option 3

NTA final key.

Chapter: Electrochemistry
Topic: Nernst Equation
Idea tested: Standard Cell Potential

Same idea in other shifts

Asked 13× in all

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.