For the electro chemical cell $\mathrm{M|M^{2+}||X|X^{2-}}$ If $\mathrm{E^0_{(M^{2+}/M)}} = 0.46\ \mathrm{V}$ and $\mathrm{E^0_{(X/X^{2-})}} = 0.34\ \mathrm{V}$. Which of the following is correct ?

Option 2: $\mathrm{M^{2+} + X^{2-} \rightarrow M + X}$ is a spontaneous reaction

$\mathrm{M + X \rightarrow M^{2+} + X^{2-}}$ is a spontaneous reaction

$\mathrm{M^{2+} + X^{2-} \rightarrow M + X}$ is a spontaneous reaction

$\mathrm{E_{cell}} = 0.80\ \mathrm{V}$

$\mathrm{E_{cell}} = -0.80\ \mathrm{V}$

JEE Main 2024 · ChemistryMultiple choiceSingle correctMediumApplication

JEE Main 5 April 2024, Shift 2, Chemistry Q64

Question 64 of 90 in this shift, Chemistry question 4 of 30, Section A.

For the electro chemical cell

\mathrm{M|M^{2+}||X|X^{2-}}

\mathrm{E^0_{(M^{2+}/M)}} = 0.46\ \mathrm{V}

and

\mathrm{E^0_{(X/X^{2-})}} = 0.34\ \mathrm{V}

. Which of the following is correct ?

(1) $\mathrm{M + X \rightarrow M^{2+} + X^{2-}}$ is a spontaneous reaction
(2) $\mathrm{M^{2+} + X^{2-} \rightarrow M + X}$ is a spontaneous reactionOfficial answer
(3) $\mathrm{E_{cell}} = 0.80\ \mathrm{V}$
(4) $\mathrm{E_{cell}} = -0.80\ \mathrm{V}$

Official answer

Option 2

Chapter: Electrochemistry
Topic: Nernst Equation
Idea tested: Standard Cell Potential

Same idea in other shifts

Asked 13× in all

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.