JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 April 2024, Shift 1, Physics Q36

Question 36 of 90 in this shift, Physics question 6 of 30, Section A.

An astronaut takes a ball of mass m from earth to space. He throws the ball into a circular orbit about earth at an altitude of

318.5

km. From earth's surface to the orbit, the change in total mechanical energy of the ball is

x\frac{GM_em}{21R_e}

. The value of

x

is (take

R_e=6370

km) :

(1) $9$
(2) $10$
(3) $11$ Official answer
(4) $12$

Official answer

Option 3

NTA final key.

Chapter: Gravitation
Topic: Orbital Mechanics
Idea tested: Energy of Orbiting Bodies

Same idea in other shifts

Asked 4× in all

2 Apr 2025, Shift 2 · Q47A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 km from the earth's surface. Kinetic…MediumNumerical value
5 Apr 2024, Shift 1 · Q36Match List I with List II : List I List II (A) Kinetic energy of planet | (I) $-\frac{GMm}{a}$ (B) Gravitation Potential energy of…MediumMatch the list
27 Jul 2022, Shift 1 · Q36Two satellites A and B, having masses in the ratio 4:3, are revolving in circular orbits of radii 3r and 4r respectively around the earth.…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.