JEE Main 2025 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 2 April 2025, Shift 2, Physics Q47

Question 47 of 75 in this shift, Physics question 22 of 25, Section B.

A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 km from the earth's surface. Kinetic energy of the satellite in this orbit is __________

\times 10^{10}

J. (Mass of earth

= 6\times10^{24}

kg, Radius of earth

= 6.4\times10^{6}

m, Gravitational constant

= 6.67\times10^{-11}\ \mathrm{Nm^2kg^{-2}}

)

Official answer

NTA final key.

Chapter: Gravitation
Topic: Orbital Mechanics
Idea tested: Energy of Orbiting Bodies

Same idea in other shifts

Asked 4× in all

5 Apr 2024, Shift 1 · Q36Match List I with List II : List I List II (A) Kinetic energy of planet | (I) $-\frac{GMm}{a}$ (B) Gravitation Potential energy of…MediumMatch the list
9 Apr 2024, Shift 1 · Q36An astronaut takes a ball of mass m from earth to space. He throws the ball into a circular orbit about earth at an altitude of $318.5$ …MediumSingle correct
27 Jul 2022, Shift 1 · Q36Two satellites A and B, having masses in the ratio 4:3, are revolving in circular orbits of radii 3r and 4r respectively around the earth.…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.