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Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 8 April 2024, Shift 2, Physics Q59

Question 59 of 90 in this shift, Physics question 29 of 30, Section B.

Two slits are 1 mm apart and the screen is located 1 m away from the slits. A light of wavelength 500 nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is ________ ×10−4\times 10^{-4} m.

Official answer

2

NTA final key.

Chapter
Wave Optics
Topic
Single Slit Diffraction
Idea tested
Diffraction Envelope in YDSE

Same idea in other shifts

Asked 2× in all
  1. 4 Apr 2025, Shift 2 · Q46In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen from slits is 2 m and the wavelength of…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.