JEE Main 8 April 2024, Shift 2, Physics Q58

Question 58 of 90 in this shift, Physics question 28 of 30, Section B.

An alternating emf

E = 110\sqrt{2}\ \sin 100t

volt is applied to a capacitor of

2\,\mu\mathrm{F}

, the rms value of current in the circuit is __________ mA.

Official answer

NTA final key.

Chapter: Alternating Current
Topic: Phasor Diagrams
Idea tested: RC Series Phasor Construction

Same idea in other shifts

Asked 2× in all

27 Jul 2022, Shift 1 · Q54To light, a 50 W, 100 V lamp is connected, in series with a capacitor of capacitance $\frac{50}{\pi\sqrt{x}}\mu F$ , with 200V, 50Hz AC…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.