JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 6 April 2024, Shift 2, Chemistry Q81

Question 81 of 90 in this shift, Chemistry question 21 of 30, Section B.

For hydrogen atom, energy of an electron in first excited state is

-3.4

eV, K.E. of the same electron of hydrogen atom is

x

eV. Value of

x

is ________

\times 10^{-1}

eV. (Nearest integer)

Official answer

NTA final key.

Chapter: Structure of Atom
Topic: Bohr's Atomic Theory
Idea tested: Total, Kinetic, and Potential Energy

Same idea in other shifts

Asked 4× in all

8 Apr 2025, Shift 2 · Q72The energy of an electron in first Bohr orbit of H-atom is −13.6 eV. The magnitude of energy value of electron in the first excited state…EasyNumerical value
13 Apr 2023, Shift 1 · Q61The energy of an electron in the first Bohr orbit of hydrogen atom is $-2.18\times10^{-18}$ J. Its energy in the third Bohr orbit…EasySingle correct
24 Feb 2021, Shift 2 · Q31According to Bohr's atomic theory : (A) Kinetic energy of electron is $\propto \frac{Z^2}{n^2}$ . (B) The product of velocity (v) of…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.