JEE Main 2025 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 8 April 2025, Shift 2, Chemistry Q72

Question 72 of 75 in this shift, Chemistry question 22 of 25, Section B.

The energy of an electron in first Bohr orbit of H-atom is −13.6 eV. The magnitude of energy value of electron in the first excited state of

\mathrm{Be^{3+}}

is __________ eV (nearest integer value)

Official answer

NTA final key.

Chapter: Structure of Atom
Topic: Bohr's Atomic Theory
Idea tested: Total, Kinetic, and Potential Energy

Same idea in other shifts

Asked 4× in all

6 Apr 2024, Shift 2 · Q81For hydrogen atom, energy of an electron in first excited state is $-3.4$ eV, K.E. of the same electron of hydrogen atom is $x$ eV. Value…EasyNumerical value
13 Apr 2023, Shift 1 · Q61The energy of an electron in the first Bohr orbit of hydrogen atom is $-2.18\times10^{-18}$ J. Its energy in the third Bohr orbit…EasySingle correct
24 Feb 2021, Shift 2 · Q31According to Bohr's atomic theory : (A) Kinetic energy of electron is $\propto \frac{Z^2}{n^2}$ . (B) The product of velocity (v) of…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.