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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 5 April 2024, Shift 2, Maths Q9

Question 9 of 90 in this shift, Maths question 9 of 30, Section A.

If the constant term in the expansion of (35x+2x53)12\left(\frac{\sqrt[5]{3}}{x}+\frac{2x}{\sqrt[3]{5}}\right)^{12}, x≠0x \neq 0, is α×28×35\alpha \times 2^8 \times \sqrt[5]{3}, then 25α25\alpha is equal to :
  1. (1)742
  2. (2)639
  3. (3)724
  4. (4)693Official answer

Official answer

Option 4

NTA final key.

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.