JEE Main 5 April 2024, Shift 2, Maths Q8

Question 8 of 90 in this shift, Maths question 8 of 30, Section A.

For

x \geq 0

, the least value of

K

, for which

4^{1+x}+4^{1-x}

\frac{K}{2}

16^x+16^{-x}

are three consecutive terms of an A.P., is equal to :

(1)10Official answer
(2)8
(3)4
(4)16

Official answer

Option 1

NTA final key.

Chapter: Sequences and Series
Topic: AP and GP
Idea tested: AM-GM Inequality Application

Same idea in other shifts

Asked 2× in all

8 Jan 2020, Shift 1 · Q56Let $f:\mathbf{R}\to\mathbf{R}$ be such that for all $x\in\mathbf{R}$ , $(2^{1+x}+2^{1-x})$ , $f(x)$ and $(3^x+3^{-x})$ are in A.P., then…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.