JEE Main 2024 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 4 April 2024, Shift 2, Maths Q25

Question 25 of 90 in this shift, Maths question 25 of 30, Section B.

Let

f:\mathbb{R}\to\mathbb{R}

be a thrice differentiable function such that

f(0)=0, f(1)=1, f(2)=-1, f(3)=2

and

f(4)=-2

. Then, the minimum number of zeros of

(3f'f''+ff''')(x)

is ___________

Official answer

NTA final key.

Chapter: Continuity and Differentiability
Topic: Rolle's Theorem
Idea tested: Higher-Order Derivative Roots

Same idea in other shifts

Asked 4× in all

30 Jan 2024, Shift 1 · Q9Let $g:\mathbf{R}\to\mathbf{R}$ be a non constant twice differentiable function such that…HardSingle correct
28 Jul 2022, Shift 1 · Q23Let $f:[0,1]\to\mathbf{R}$ be a twice differentiable function in $(0,1)$ such that $f(0)=3$ and $f(1)=5$ . If the line $y=2x+3$ intersects…MediumNumerical value
31 Aug 2021, Shift 2 · Q68Let $f$ be any continuous function on $[0, 2]$ and twice differentiable on $(0, 2)$ . If $f(0) = 0$ , $f(1) = 1$ and $f(2) = 2$ , then :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.