JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 15 April 2023, Shift 1, Physics Q45

Question 45 of 90 in this shift, Physics question 15 of 30, Section A.

The de Broglie wavelength of an electron having kinetic energy E is

\lambda

. If the kinetic energy of electron becomes

\frac{E}{4}

, then its de-Broglie wavelength will be :

(1) $\frac{\lambda}{2}$
(2) $2\lambda$ Official answer
(3) $\frac{\lambda}{\sqrt{2}}$
(4) $\sqrt{2}\lambda$

Official answer

Option 2

NTA final key.

Chapter: Dual Nature of Radiation and Matter
Topic: Matter Waves
Idea tested: Wavelength from Kinetic Energy

Same idea in other shifts

Asked 7× in all

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26 Aug 2021, Shift 2 · Q8The de-Broglie wavelength of a particle having kinetic energy E is $\lambda$ . How much extra energy must be given to this particle so that…MediumSingle correct
25 Jul 2021, Shift 1 · Q6What should be the order of arrangement of de-Broglie wavelength of electron ( $\lambda_e$ ), an $\alpha$ -particle ( $\lambda_\alpha$ ) and…EasySingle correct
9 Jan 2020, Shift 1 · Q17A particle moving with kinetic energy E has de Broglie wavelength $\lambda$ . If energy $\Delta E$ is added to its energy, the wavelength…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.