JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 15 April 2023, Shift 1, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

The position vector of a particle related to time

t

is given by

\vec{r} = (10t\hat{i} + 15t^2\hat{j} + 7\hat{k})\,m

The direction of net force experienced by the particle is :

(1)Positive $x$ - axis
(2)Positive $y$ - axisOfficial answer
(3)Positive $z$ - axis
(4)In $x$ - $y$ plane

Official answer

Option 2

NTA final key.

Chapter: Laws of Motion
Topic: Newton's Laws of Motion
Idea tested: Momentum Formulation (F = dp/dt)

Same idea in other shifts

Asked 7× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.