JEE Main 2023 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 13 April 2023, Shift 1, Maths Q12

Question 12 of 90 in this shift, Maths question 12 of 30, Section A.

The area of the region enclosed by the curve

f(x)=\max\{\sin x,\cos x\}

-\pi\leq x\leq\pi

and the

x

-axis is

(1) $2\sqrt{2}\left(\sqrt{2}+1\right)$
(2) $4$ Official answer
(3) $2\left(\sqrt{2}+1\right)$
(4) $4\left(\sqrt{2}\right)$

Official answer

Option 2

NTA final key.

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Area Involving Max/Min Functions

Same idea in other shifts

Asked 8× in all

4 Apr 2026, Shift 1 · Q18The area of the region $\{(x,y): y\le\pi-|x|,\ y\le|x\sin x|,\ y\ge0\}$ is:HardSingle correct
3 Apr 2025, Shift 1 · Q25The area of the region bounded by the curve $y = \max\{|x|, x|x-2|\}$ , the $x$ -axis and the lines $x = -2$ and $x = 4$ is equal to ______MediumNumerical value
7 Apr 2025, Shift 2 · Q20If the area of the region $\{(x,y): 1+x^2\le y\le \min\{x+7,\ 11-3x\}\}$ is $A$ , then $3A$ is equal toMediumSingle correct
8 Apr 2024, Shift 1 · Q27Let the area of the region enclosed by the curve $y=\min\{\sin x,\cos x\}$ and the $x$ -axis between $x=-\pi$ to $x=\pi$ be $A$ . Then $A^2$ …MediumNumerical value
8 Apr 2023, Shift 2 · Q27Let the area enclosed by the lines $x + y = 2$ , $y = 0$ , $x = 0$ and the curve $f(x) = \min\left\{x^2 + \frac{3}{4}, 1 + [x]\right\}$ …HardNumerical value
25 Jul 2022, Shift 1 · Q8The area of the region given by $A=\{(x,y):x^2\le y\le\min\{x+2,\,4-3x\}\}$ is :MediumSingle correct
17 Mar 2021, Shift 2 · Q87Let $f:[-3, 1]\to\mathbf{R}$ be given as…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.