Learn

Saturday, 31 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 7 April 2025, Shift 2, Maths Q20

Question 20 of 75 in this shift, Maths question 20 of 25, Section A.

If the area of the region {(x,y):1+x2≤y≤min⁡{x+7, 11−3x}}\{(x,y): 1+x^2\le y\le \min\{x+7,\ 11-3x\}\} is AA, then 3A3A is equal to
  1. (1)50Official answer
  2. (2)49
  3. (3)47
  4. (4)46

Official answer

Option 1

NTA final key.

Same idea in other shifts

Asked 8× in all
  1. 4 Apr 2026, Shift 1 · Q18The area of the region {(x,y):y≤π−∣x∣, y≤∣xsin⁡x∣, y≥0}\{(x,y): y\le\pi-|x|,\ y\le|x\sin x|,\ y\ge0\} is:HardSingle correct
  2. 3 Apr 2025, Shift 1 · Q25The area of the region bounded by the curve y=max⁡{∣x∣,x∣x−2∣}y = \max\{|x|, x|x-2|\}, the xx-axis and the lines x=−2x = -2 and x=4x = 4 is equal to ______MediumNumerical value
  3. 8 Apr 2024, Shift 1 · Q27Let the area of the region enclosed by the curve y=min⁡{sin⁡x,cos⁡x}y=\min\{\sin x,\cos x\} and the xx-axis between x=−πx=-\pi to x=πx=\pi be AA. Then A2A^2…MediumNumerical value
  4. 8 Apr 2023, Shift 2 · Q27Let the area enclosed by the lines x+y=2x + y = 2, y=0y = 0, x=0x = 0 and the curve f(x)=min⁡{x2+34,1+[x]}f(x) = \min\left\{x^2 + \frac{3}{4}, 1 + [x]\right\}…HardNumerical value
  5. 13 Apr 2023, Shift 1 · Q12The area of the region enclosed by the curve f(x)=max⁡{sin⁡x,cos⁡x}f(x)=\max\{\sin x,\cos x\}, −π≤x≤π-\pi\leq x\leq\pi and the xx-axis isMediumSingle correct
  6. 25 Jul 2022, Shift 1 · Q8The area of the region given by A={(x,y):x2≤y≤min⁡{x+2, 4−3x}}A=\{(x,y):x^2\le y\le\min\{x+2,\,4-3x\}\} is :MediumSingle correct
  7. 17 Mar 2021, Shift 2 · Q87Let f:[−3,1]→Rf:[-3, 1]\to\mathbf{R} be given as…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.