JEE Main 2023 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 11 April 2023, Shift 2, Physics Q57

Question 57 of 90 in this shift, Physics question 27 of 30, Section B.

A coil has an inductance of

2\mathrm{H}

and resistance of

4\ \Omega

. A

10\ \mathrm{V}

is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ____________

\times10^{-2}\mathrm{J}

Official answer

625

NTA final key.

Chapter: Electromagnetic Induction
Topic: Inductance
Idea tested: Energy Stored in Inductors

Same idea in other shifts

Asked 7× in all

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25 Jun 2022, Shift 1 · Q59The current in a coil of self inductance 2.0 H is increasing according to I=2 sin( $t^2$ ) A. The amount of energy spent during the period…MediumNumerical value
3 Aug 2021, Shift 1 · Q24An inductor coil stores 32 J of magnetic field energy and dissipates energy as heat at the rate of 64 W when a current of 8 A is passed…MediumNumerical value
26 Aug 2021, Shift 1 · Q9An inductor coil stores 64 J of magnetic field energy and dissipates energy at the rate of 640 W when a current of 8 A is passed through…MediumSingle correct
25 Feb 2021, Shift 1 · Q23A coil of inductance 2 H having negligible resistance is connected to a source of supply whose voltage is given by V=3t volt. (where t is…MediumNumerical value
4 Sep 2020, Shift 2 · Q15A series L-R circuit is connected to a battery of emf V. If the circuit is switched on at $t=0$ , then the time at which the energy stored…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.