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JEE Main 3 August 2021, Shift 1, Physics Q24
Question 24 of 90 in this shift, Physics question 24 of 30, Section B.
An inductor coil stores 32 J of magnetic field energy and dissipates energy as heat at the rate of 64 W when a current of 8 A is passed through it. When this coil is joined across an ideal battery, the time constant of the circuit is _________s (second).
Official answer
1
NTA final key.
- Chapter
- Alternating Current
- Topic
- Inductance
- Idea tested
- Energy Stored in Inductors