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Saturday, 31 October

JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 10 April 2023, Shift 1, Physics Q46

Question 46 of 90 in this shift, Physics question 16 of 30, Section A.

The de Broglie wavelength of a molecule in a gas at room temperature (300 K) is λ1\lambda_1. If the temperature of the gas is increased to 600 K, then the de Broglie wavelength of the same gas molecule becomes
  1. (1)12λ1\frac{1}{2}\lambda_1
  2. (2)2λ12\lambda_1
  3. (3)12λ1\frac{1}{\sqrt{2}}\lambda_1Official answer
  4. (4)2 λ1\sqrt{2}\,\lambda_1

Official answer

Option 3

NTA final key.