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Saturday, 31 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2026, Shift 1, Physics Q35

Question 35 of 75 in this shift, Physics question 10 of 25, Section A.

An electron of mass mm is moving in an electric field E⃗=−2E0i^\vec{E} = -2E_0\hat{i} (E0E_0 = constant >0> 0), with an initial velocity V⃗=v0i^\vec{V} = v_0\hat{i} (v0v_0 = constant >0> 0). If λ0=h4mv0\lambda_0 = \frac{h}{4mv_0}, its de Broglie wavelength at time tt is ________. (ee = charge of electron)
  1. (1)4λ0[1−E0e2mtv0]\frac{4\lambda_0}{\left[1 - \frac{E_0 e}{2m}\frac{t}{v_0}\right]}
  2. (2)4λ0[1+E0e2mtv0]\frac{4\lambda_0}{\left[1 + \frac{E_0 e}{2m}\frac{t}{v_0}\right]}
  3. (3)4λ0[1+2E0emtv0]\frac{4\lambda_0}{\left[1 + \frac{2E_0 e}{m}\frac{t}{v_0}\right]}Official answer
  4. (4)4λ0[1−2E0emtv0]\frac{4\lambda_0}{\left[1 - \frac{2E_0 e}{m}\frac{t}{v_0}\right]}

Official answer

Option 3

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 8 Jan 2020, Shift 2 · Q18An electron (mass m) with initial velocity v⃗=v0 i^+v0 j^\vec{v}=v_0\,\hat{i}+v_0\,\hat{j} is in an electric field E⃗=−E0 k^\vec{E}=-E_0\,\hat{k}. If…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.