JEE Main 2020 (8 Jan, Shift 2) Physics Q18: Matter Waves

Question

An electron (mass m) with initial velocity $\vec{v}=v_0\,\hat{i}+v_0\,\hat{j}$ is in an electric field $\vec{E}=-E_0\,\hat{k}$. If $\lambda_0$ is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by :

Accepted Answer

Option 2: $\frac{\lambda_0}{\sqrt{1+\frac{e^2E^2t^2}{2m^2v_0^2}}}$

Answer

$\frac{\lambda_0}{\sqrt{1+\frac{e^2E_0^2t^2}{m^2v_0^2}}}$

Answer

$\frac{\lambda_0}{\sqrt{1+\frac{e^2E^2t^2}{2m^2v_0^2}}}$

Answer

$\frac{\lambda_0}{\sqrt{2+\frac{e^2E^2t^2}{m^2v_0^2}}}$

Answer

$\frac{\lambda_0\sqrt{2}}{\sqrt{1+\frac{e^2E^2t^2}{m^2v_0^2}}}$

JEE Main 8 January 2020, Shift 2, Physics Q18

Same idea in other shifts